Kapitel IV. Grenzfälle.
265
In (1+x) =
x
1+
х
х
1+
6
1 +
aretghypx=ln 1+x
1- -x
x
aretg x =
x
1+
يع
1+
2
x
10
3
1+ x
10
3
1+
x
14
1+
1
x2
2 2
3 5
2
1+
3
25
2
x
3
1+
.
5
X2
3 3
1
5 7
4 4
7 9
1+
3
تت -
7
22
7
•
1+
4
9
x2
1
x
1
1
1+
Ꮖ
3
1
--
X
6
1+
x
1
1
х
10
1
1+
Ꮖ
10